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Alborosie
3 years ago
6

Write 2350 million in standard form. Write 25 x 10^6 in standard form.

Mathematics
1 answer:
masha68 [24]3 years ago
6 0

2350 million in standard form is:

2,350,000,000

2.5000000 x 10^7

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A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 3 : 1.
S_A_V [24]

Coordinates of point C: (1,-1)

Step-by-step explanation:

In this problem, A, B and C are collinear, and B is between A and C.

The ratio AB : BC is 3 : 1.

This means that we can write the following two equations:

x_B-x_A = 3(x_C-x_B)\\y_B-y_A=3(y_X-y_B)

where:

(x_A,y_A)=(-7,3) are the coordinates of point A

(x_B,y_B)=(-1,0) are the coordinates of point B

(x_C,y_C) are the coordinates of point C

Solving the equation for x_C,

x_C = x_B + \frac{x_B-x_A}{3}=-1+\frac{-1-(-7)}{3}=1

Solving the equation for y_C,

y_C=y_B + \frac{y_B-y_A}{3}=0+\frac{0-3}{3}=-1

So, the coordinates of point C are

C(-1,1)

Learn more about how to divide segments:

brainly.com/question/3269852

brainly.com/question/11280112

#LearnwithBrainly

4 0
3 years ago
James can jog twice as fast as he can walk. He was able to jog the first 9 miles to his grandmother’s house, but then he tired a
dimulka [17.4K]

Answer:

6 mile/hour

Explanation :



Let the speed of walking of James = x mile/hour


speed of jogging = 2x mile/hour


9/2x + 1.5/x = 2


= > (9 + 3)/2x = 2


= > 12 = 4x


= > x = 3


Average speed of walking = 3 mile/hour


Average speed of jogging = 2 * 3 = 6 mile/hour

5 0
3 years ago
An experiment consists of drawing a marble out of a bag, observing the color, and then placing it back in the bag. Suppose the e
Elan Coil [88]
The experimental data suggest that

\mathbb P(\text{red})\approx\dfrac{38}{75}
\mathbb P(\text{blue})\approx\dfrac{23}{75}
\mathbb P(\text{green})\approx\dfrac{11}{75}
\mathbb P(\text{yellow})\approx\dfrac3{75}

Because the marble is replaced after being drawn, and so the number of marbles of a given color remains the same, the event of drawing any given color is independent of what was drawn before. So

\mathbb P(\text{2 consecutive yellows})\approx\dfrac3{75}\cdot\dfrac3{75}=\dfrac1{625}
5 0
4 years ago
Read 2 more answers
Identify the solution set of 3 In 4 = 2 In x.<br> -{6}<br> -{-8,8}<br> -(8)
o-na [289]

Option C: The solution set is \{8\}

Explanation:

The expression is 3 \ln 4=2 \ln x

Now, let us find the solution set.

Switch sides, we get,

2 \ln x=3 \ln 4

Dividing by 2 on both sides, we have,

\ln x=\frac{3 \ln 4}{2}

Thus,  \ln 4=\ln 2^2=2\ln 2

Hence, the above expression becomes,

\ln x=\frac{3 \cdot 2 \ln (2)}{2}

Simplifying, we get,

\ln x=3 \ln 2

Applying the log rule, we get,

$$\ln x$=\ln \left(2^{3}\right)$

Simplifying, we have,

$$\ln x$=\ln \left8\right$

Applying the log rule, we have,

x=8

Thus, the solution set is \{8\}

Hence, Option C is the correct answer.

5 0
4 years ago
From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin
borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

C_{n,x} = \frac{12!}{4!(8)!} = 495

495 combinations of 4 students can be selected.

8 0
3 years ago
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