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3 years ago

In the figure to the right, AB=7 1/2m, BC=2 1/4 m, and DE=1 1/4m. Find the perimeter of the figure if all angles are right.

Mathematics

2 answers:

Eduardwww [97]3 years ago

5 0

Answer:

22 meters

Step-by-step explanation:

What we know:

Side AB is 7 1/2 m long, Side BC is 2 1/4 m long, and Side DE is 1 1/4 m long.

Saying Sides AH and FG are the same as Sides DE and BC respectively, we can add another 3 1/2 m to the perimeter.

If CD, EF and GH are each 1/3 of AB, then 7 1/2 is added again.

7.5 + (2.5 * 3) * (2.25 * 2) + (1.25 * 2)

7.5 + 7.5 + 4.5 + 2.5

15 + 7

The perimeter is 22 meters.

sveta [45]3 years ago

4 0

22 meters is the perimeter i think i calculated that right but hoped it helped☺️

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when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

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When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

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