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3 years ago

5

In the figure to the right, AB=7 1/2m, BC=2 1/4 m, and DE=1 1/4m. Find the perimeter of the figure if all angles are right.

2 answers:

Eduardwww [97]3 years ago

5 0

Answer:

22 meters

Step-by-step explanation:

What we know:

Side AB is 7 1/2 m long, Side BC is 2 1/4 m long, and Side DE is 1 1/4 m long.

Saying Sides AH and FG are the same as Sides DE and BC respectively, we can add another 3 1/2 m to the perimeter.

If CD, EF and GH are each 1/3 of AB, then 7 1/2 is added again.

7.5 + (2.5 * 3) * (2.25 * 2) + (1.25 * 2)

7.5 + 7.5 + 4.5 + 2.5

15 + 7

The perimeter is 22 meters.

sveta [45]3 years ago

4 0

22 meters is the perimeter i think i calculated that right but hoped it helped☺️

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Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

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$0.09R(1 - 0.00025R) - 0.001RW = 0$

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Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

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Split

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$0.00004R = 0.02$

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$R = \frac{0.02}{0.00004}$

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$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

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Collect like terms

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Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

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$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

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$(R,W) \to (4000,0)$

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$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

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