Question

what is the completely factored form of t^4 − 16? (t^2 4)(t^2 − 4) (t^2 4)(t 2)(t − 2) (t^2 4)(t − 2)(t − 2) (t 2)(t 2)(t 2)(t − 2)

Answer 1

$Use:a^2-b^2=(a-b)(a+b)\\\\t^4-16=(t^2)^2-4^2=(t^2-4)(t^2+4)=(t^2-2^2)(t^2+4)=(t-2)(t+2)(t^2+4)$