Select all that apply to similar figures.

Plz can someone help me in am doing a unit test

patriot [66]

Answer:

n-31=52

substitute 83 from the variable in the equation.

other one not sure

7 0

3 years ago

Read 2 more answers

Please help me asap with my grade 11 trigonometry math! I'll give brainliest, please help, thank you. *URGENT*

tia_tia [17]

Answer:

37.8579

This value is approximate and rounded to four decimal places

===============================================

Explanation:

The tangent function is being applied to some unknown angle x. To isolate x, we undo whatever tangent is doing. So we apply the inverse function. Specifically the inverse tangent function. This is also known as "arctangent" and your calculator most likely shows it as a button with a "-1" exponent above the "tan"

So apply the arctangent to both sides to get

tan(x) = 0.7773

arctan(tan(x)) = arctan(0.7773)

x = 37.8579

6 0

2 years ago

Read 2 more answers

2. When the degree of rotation is negative, what is the<br> direction of the rotation?

disa [49]

Answer:

clockwise

Step-by-step explanation:

Conventionally, positive angles in the Cartesian coordinate plane are measured counterclockwise from the +x axis. Rotation in the negative direction is the opposite of that, so is clockwise.

3 0

3 years ago

If both dimensions in a parallelogram are doubled then which statements about its area will be true

valentina_108 [34]

Well as you can see my guy this is obviously 69999 because I said so

3 0

3 years ago

Assume that foot lengths of women are normally distributed with a mean of 9.6 in and a standard deviation of 0.5 in.a. Find the

Makovka662 [10]

Answer:

a) 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b) 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c) 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 9.6, \sigma = 0.5$ .