Answer:
02 High Schools would be selected from the stratum with a percent-free-lunch value of 40 less than or equals x.
Step-by-step explanation:
As the sample size needed is 25 and total schools are 100 so this indicate 1 school in each 4 schools is to be selected. This is given as

Now as the schools with percent free lunch are 8 so now

So only 2 schools will be selected in this regard.
Answer:
a)
degrees
b) 
Step-by-step explanation:
An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

a) Calculate I at (T ,H) = (95, 50).
degrees
(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.
This is the partial derivative of I in function of T, that is
. So



148, 6-1.75=5.25, then.... 625/5.25& round up.... its 148.
Answer:
y = -4x + 9
O.R. y = 9- 4x
(both answers are equivalent, the same)
Step-by-step explanation:
1. finding gradient of perpendicular line to the equation given.
2. use the point provided in the wuestion and substitute it into the linear form of your slope-intercept form, which in my country is called the linear form, meaning straight line graph.
3. get answers by finding the y-intercept of the equation wanted.
note:
y = mx + c is how and what i use in my school as the linear form, altho every school is different and I understand that, so do check again with your teacher if it is how you do such type of questions.
Answer is number 2
F(3)= (3-1)^2+ 3(3)=4+9= 13 so the first option is wrong
F(-2)= (-2-1)^2+ 3(-2)= 9-6=3 third options is wrong
F(-15)= (-15-1)^2 +3(-15)= 256-45= 211 fourth option is wrong