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Damm [24]
3 years ago
7

Solve x/12+1/3=5/6 please help me resolve

Mathematics
1 answer:
viktelen [127]3 years ago
4 0

Subtract 1/3 from both sides

x/12 = 5/6 - 1/3

Simplify 5/6 - 1/3 to 1/2

x/12 = 1/2

Multiply both sides by 12

x = 12 × 12

Simplify 1/2 × 12 to 12/2

x = 12/2

Simplify 12/2 to 6

<u>x = 6</u>

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A football club won 90 of its 120 games in a season. What percentage of games were won
liberstina [14]

Answer:

75%

Step-by-step explanation:

Because if u do 90/120 u get 0.75 and divide it by 100 to get %

so the answer is 75%

Remember to give 5 stars and thank me if the answer is correct

8 0
3 years ago
How many different positive integers can be represented as a difference of two distinct members of the set {1, 2, 3, 4, 5, 6}?
slega [8]

For the difference to be positive, when both the minuend and the subtrahend are positive, the former must be greater than the latter.

Therefore

minuend = 2 ⇒ subtrahend = 1 ← 1 number

minuend = 3 ⇒ subtrahend = 1,2 ← 2 numbers

minuend = 4 ⇒ subtrahend = 1,2,3 ← 3 numbers

minuend = 5 ⇒ subtrahend = 1,2,3,4 ← 4 numbers

minuend = 6 ⇒ subtrahend = 1,2,3,4,5 ← 5 numbers

1+2+3+4+5=<u>15</u>

5 0
3 years ago
If MN=NQ and MQ=QR=RP, calculate for x​
Akimi4 [234]

Answer:

  • C. 18°

Step-by-step explanation:

  • <em>Refer to attached diagram</em>
<h3>Given </h3>
  • MN = NQ
  • MQ = QR = RP
  • NMR = 3x
  • QMR = x
<h3>To find</h3>
  • Value of x
<h3>Solution</h3>
  • MN = NQ  ⇒ ∠MRN = ∠QMN = 3x+x = 4x
  • MQ = QR ⇒ ∠MRQ = ∠QMR = x

<u>RQP is exterior angle of ΔMQR ⇒ </u>

  • ∠RQP = x + x = 2x

<u>QR = RP ⇒ </u>

  • ∠RPQ = ∠RQP = 2x

<u>∠QRN is exterior angle of ΔQRP ⇒ </u>

  • ∠QRN = 2x + 2x = 4x
  • ∠MRN = ∠QRN - ∠QRM = 4x - x = 3x

<u>∠MRN = ∠NMR = 3x ⇒ </u>

  • NR = MQ

<u>NR = MQ ⇒ </u>

  • ∠NQR = ∠QRN = 4x

<u>We now have a straight angle MQP:</u>

  • ∠MQP = ∠MQN + ∠RQN + ∠RQP
  • 180° = 4x + 4x + 2x
  • 10x = 180°
  • x = 18°

Correct choice is C

7 0
3 years ago
The drama club was selling ticketsto the school play. Adult ticketscost $8.00 each, and studenttickets cost $5.00 each. The litt
BlackZzzverrR [31]

We are given a problem that can be solved using a system of linear equations. Let A, be the number of adults, and S the number of students. Since there are in total 142 people and there were two days, this means that the sum of the number of adults and the number of students must be 284, which can be written mathematically as follows:

A+S=284,(1)

This is our first equation. The second equation is found using the total sales of $1948. Since the ticket per adult is $8 and per student is $5, we have the following equations:

8A+5S=1948,(2)

To solve this equation we will solve for A in equation (1), by subtracting S to both sides;

\begin{gathered} A+S-S=284-S \\ A=284-S \end{gathered}

Now we will replace this value in equation (2):

8(284-S)+5S=1948

Now we will apply the distributive property:

2272-8S+5S=1948

Addins like terms:

2272-3S=1948

Subtracting 2272 to both sides;

\begin{gathered} 2272-2272-3S=1948-2272 \\ -3S=-324 \end{gathered}

Dividing both sides by -3:

S=-\frac{324}{-3}=108

Now we replace this value in equation (1), where we have already solved for A:

\begin{gathered} A=248-108 \\ A=140 \end{gathered}

Therefore, there were sold 108 student tickets and 140 adult tickets.

3 0
1 year ago
Find simple interest <br>Rs.6500 for 2years 3months at<br>6percent per annum<br><br>​
maks197457 [2]

<h2>Question:</h2>

find simple interest

Rs.6500 for 2years 3months at

6percent per annum

<h2>Solution :</h2>

To find the simple interest , We'd use the following formula:-

<h2>P×R×T/100</h2>
  • P= 6500
  • R=6
  • 2.25 (2 years+ 3 month)

.°.

S.I = 65×13.5

S.I = Rs.877.50

Hope it helps

-------☆゚.・。゚ᵴɒƙυᴚᴀ_ƨȶäᴎ❀

4 0
3 years ago
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