Answer: The set does not have a solution
Step-by-step explanation:
Adding Equations 1 & 3 we get 5x = 7. This gives x = 7/5
Putting this value of x in eq. 2 we get
-2y + 2z = -1-(7/5) or
2y - 2z = 12/5 or 5y - 5z = 6
Multiplying eq. 1 by 2 we get
4x + 2y - 2z = 6
adding this with eq. 2 we get 5x = 5 or x = 1
As the common solution for x from equations 1&3 does not satisfy eq. 1&2 it comes out that the three equations do not have a common solution.
Same can be verified by using different sets of two equations also.
Answer:
.18
Step-by-step explanation:
if ^2 is an exponent
(-16t*-16t)+8t+48
(258t+8t)+48
266t+48
48/266
.180
or .18
This is not possible. Why not? Because the smallest the variance can get is 0.
Recall that 's' represents the standard deviation, so s^2 is the variance. It basically measures how spread out the values are. The higher the variance, the more spread out the data. You can think of it as "average distance from the mean". If the variance is 0, then all of the values are at the same point. So you could have a list like {2,2,2,2,2} which has variance 0. We cannot get any smaller variance than that. If your teacher insists all the values in the list are different, then the variance will be greater than 0.
0.38 if you divide 100 by 8 you get 0.125 and when you multiply it by 3 you get 0.375. 0.38>0.375
In(xy) = e^(x+y)
(xy)'/xy = (x+y)' e^(x+y)
(x'y + xy')/xy = (1+y') e^(x+y)
(y + xy')/xy = (1+y')e^(x+y) and simplify
Hope this helps
