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n200080 [17]
3 years ago
10

What is the probability that more than twelve loads occur during a 4-year period? (Round your answer to three decimal places.)

Mathematics
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

Given that an article suggests

that a Poisson process can be used to represent the occurrence of

structural loads over time. Suppose the mean time between occurrences of

loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a

4-year period? c). How long must a time period be so that the probability of no loads

occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a

4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads

occurring during that period is at most 0.3 is given by: 3.3 years

Step-by-step explanation:

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11.1.30<br> How many three-digit even numbers are possible if the leftmost digit cannot be zero?
Ann [662]

The total number of 3 digit even numbers is 450

Step-by-step explanation:

Step 1 :

We need to determine the  number of 3 digit numbers which is even and the leftmost digit is not zero .

The  3 digits with left most digit not equal to zero starts from 100 and goes up to 998

If we consider only the even 3 digit numbers in this interval, this would form an arithmetic progression with the first number a = 100 and the common difference d = 2.

Step 2:

The last number l  in this series is 998 .

So we have

a = 100

l = 998

d = 2

The nth term in the arithmetic progression is given by a + (n-1) d

so substituting the above values we get

100 + (n-1) 2 = 998

2n = 900  => n = 450

Step 3 :

Answer :

The total number of 3 digit even numbers is 450

4 0
3 years ago
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VMariaS [17]

Answer:

Option C. Stem Leaves 6 7 7 2 5 8 5 7 9 9 9 0 9 10 0

Option D.

Step-by-step explanation:

The data values are 67, 72, 85, 75, 89, 89, 87, 90, 99 and 100.

Arranging the data values in ascending order

67, 72, 75, 85, 87, 89, 89, 90, 99, 100

The stem and lead plot can be shown under and stem is denoted as "S" whereas leaves are denoted as "L".

S  L

6  7

7  2 5

8  5 7 9 9

9  0 9

10  0

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Answer:

44u-36

Step-by-step explanation:

Apply the distributive property.

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Multiply −7 by −6.

42u−6⋅6+2u

Multiply −6 by 6.

42u−36+2u

Add 42u and 2u.

44u-36

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N= -4

-4/2+5=3

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3 years ago
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