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zvonat [6]
3 years ago
14

Do rational expressions contain logarithmic functions? A. always B. sometimes C. never

Mathematics
2 answers:
makkiz [27]3 years ago
5 0
<span>By definition, rational expression is the ratio of two polynomial function Q(x) and P(x), where P(x) should not be zero. Polynomial function is defined as continuous for all real number. But, Logarithmic function is continuous only for any value of x>0. Hence,Rational expression SOMETIMES contain logarithmic functions and it should not be located at the denominator.</span>
bazaltina [42]3 years ago
3 0

The right answer is C. never


The quotient of two algebraic expressions is a<em> fractional expression. </em> Moreover, the quotient of two <em>polynomials</em> such as:


\frac{1}{x} \\ \\ \frac{3x-2}{1+x} \\ \\ \frac{x^2-4}{x^2+2}


is called a rational expression. So according to this definition rational expressions does not contain logarithmic functions. In fact, a rational expression is an expression that is the ratio of two polynomials like this:


f(x)=\frac{P(x)}{Q(x)} \\ \\ with \ Q(x) \neq 0

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58.5 mg

Step-by-step explanation:

Drink: 130% of RDA of vitamin X

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<h2>Answer and Explanation to questions 13,14,15</h2>

13) \mathbf{\overline{XY}\cong\overline{CD}}        as given in the question.

14) \mathbf{\overline{XY}\cong\overline{YZ}}          Since Y is the midpoint of XZ. So, Y will divide XZ in equal halves into XY and YZ.

15) \mathbf{\overline{CD}\cong\overline{YZ}}

\because\overline{\textrm{XY}}\cong\overline{\textrm{CD}} and \overline{\textrm{XY}}\cong\overline{\textrm{YZ}} . So, \overline{\textrm{CD}}\cong\overline{\textrm{YZ}}

<h2>Answer and Explanation to questions 16,17,18</h2>

∠3 is supplementary to ∠1 means: ∠3 + ∠1 = 180°

And, according to figure ∠1 + ∠2 = 180° as ∠1 and ∠2 form a straight line.

∠3 + ∠1 = 180°    .............(i)

∠1 + ∠2 = 180°    .............(ii)

subtracting equation (i) and (ii) will give ∠3 = ∠2   ..........(iii)

15) ∠3 is supplementary to ∠1                        as given in the question

16) ∠2 is supplementary to ∠1                        as shown be equation (ii)

18) ∠3 ≅ ∠2                                                      as shown by equation (iii)

<h2>Answer and Explanation to questions 19</h2>

∠3 and ∠4 form a straight line. Therefore, ∠3 + ∠4 = 180°   .......(i)

∠4 and ∠5 form a straight line. Therefore, ∠4 + ∠5 = 180°   .......(ii)

subtracting equation (i) and (ii)

∠3 + ∠4 - (∠4 + ∠5) = 180°-(180°)

∠3 + ∠4 - ∠4 - ∠5 = 180°-180°

∠3 - ∠5 = 0

∴ ∠3 = ∠5     (Hence Proved)

4 0
3 years ago
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