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zvonat [6]
3 years ago
14

Do rational expressions contain logarithmic functions? A. always B. sometimes C. never

Mathematics
2 answers:
makkiz [27]3 years ago
5 0
<span>By definition, rational expression is the ratio of two polynomial function Q(x) and P(x), where P(x) should not be zero. Polynomial function is defined as continuous for all real number. But, Logarithmic function is continuous only for any value of x>0. Hence,Rational expression SOMETIMES contain logarithmic functions and it should not be located at the denominator.</span>
bazaltina [42]3 years ago
3 0

The right answer is C. never


The quotient of two algebraic expressions is a<em> fractional expression. </em> Moreover, the quotient of two <em>polynomials</em> such as:


\frac{1}{x} \\ \\ \frac{3x-2}{1+x} \\ \\ \frac{x^2-4}{x^2+2}


is called a rational expression. So according to this definition rational expressions does not contain logarithmic functions. In fact, a rational expression is an expression that is the ratio of two polynomials like this:


f(x)=\frac{P(x)}{Q(x)} \\ \\ with \ Q(x) \neq 0

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Nonamiya [84]
Cos 157.5º=-cos (180º-157.5º)=-cos 22.5=-cos(45/2)

cos Ф/2=⁺₋√((1+cosФ)/2).

In this case 157.5º is in the second quadrant, therefore we use the following equation:
cos Ф/2=-√((1+cosФ)/2).          (we will have a negative number)

cos 157.5º=-cos (45/2)=-√((1+cos 45º)/2)
=-√((1+√2/2)/2)
=-√((2+√2)/4)
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Answer: cos 157.5º= -√(2+√2) / 2

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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