Answer:
5n + 10d represented the money spend by the Amy in playing board games of cost $5 and $10 .
Step-by-step explanation:
As given
Amy and Mary are playing a board game that uses game money if $5 and $10.
At the end of the game, Amy has n bills worth $5 each and d bills worth $10 each .
Total amount of n bills = 5n
Total amount of d bills = 10d
Thus
Total money spend by the Amy in playing board games = Total amount of n bills + Total amount of d bills
= 5n + 10d
Therefore 5n + 10d represented the money spend by the Amy in playing board games of cost $5 and $10 .
A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
2 minutes = 1.20 dollars for price of sundae.in 4 hours how many minutes are there?=> 60 * 4 hours = 240 minutes => 240 / 2minutes per sundae = 120 minutes => 120 * 1.20 = 144 dollars in 4 hoursOr 72 dollars in 2 hours
Hello!
First you have to list the data in both classes
Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90
Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
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First we are going to find the mode and mean of class A
The mode is the number that appears the most
The number that appears the most is 61
The mode is 61
To find the mean you add all the numbers together and divide the sum by the amount of numbers added
41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069
Divide this by the amount of numbers added
1069 / 18 = 59.3888...
The mean is 59.3888
The mode is 61 and the mean is 59.39 for class A
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We are going to find the range and median for class B
To find the range you subtract the smallest number from the largest on
The smallest number is 41
The largest number is 95
Subtract these
95 - 41 = 54
The range is 54
To find the median you list the numbers from least to greatest and look for the number in the middle
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
The number in the middle is 78
The range is 54 and the median is 78
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Hope this helps!
Ok, so remember
the legnth of the longest side must be LESS THAN the sum of the measures of the other 2 sides
if no longest side (becasue it has 2 longest sides or 3 equal sides), then it can form a triangle
so the longest side is 36
36 must be less than the sum of 15 and 20
36<15+20
36<35
false
therfor it cannot form a triangle
try it yourself, you cannot connect them that way
