Question

The contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces. We are interested in testing to determine whether the variance of the population is significantly more than 0.003. What is the alternative hypothesis?

Answer 1

Answer: $H_a: \sigma^2>0.003$

Step-by-step explanation:

Given : The contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces.

To test : The variance of the population is significantly more than 0.003.

We know that the alternative hypothesis can have > , < or ≠.

And The null hypothesis contains  ≤  , ≥ or = .

Since the the interest of testing has strictly more than sign.

Then the alternative hypothesis for this test will be :-

$H_a: \sigma^2>0.003$