<h3>Given</h3>
x² +y = 0
x³ -12x -y = 0
<h3>Find</h3>
the intersection point(s) (x, y)
<h3>Solution</h3>
Add the two equations together, then factor.
... (x² +y) + (x³ -12x -y) = 0 + 0
... x³ +x² -12x = 0
... x(x +4)(x -3) = 0
Then x = {0, -4, 3}.
The corresponding y-values are
... y = -x² = {0, -16, -9}
The points of intersection are (-4, -16), (0, 0), (3, -9)
You have written 0 = 4x.
The value of x that makes it true is x = 0, given that 4 times 0 is 0.
Nevertheless, I think you wanted to write 0 = 4 ^x (this is 4 raised to the power 4).
In that case, there is not any valued of x that satisfies the equation. This is, the equation is always false.
That is because, there is not any value of x for which 4^x is zero. The range of this function is al the positive values of x, which exclude zero.
Answer:
-8x+21
Step-by-step explanation:
Use the distributive property.
