All categories

2 years ago

If two polygons are similar, must they also be congruent?

Mathematics

1 answer:

NISA [10]2 years ago

4 0

Answer:

I think No

Explanation:

We say two figures are similar if they have the same shape, but not necessarily the same size. <u>If they also have the same size</u>, we say they are congruent.

<h2> $hope \: this \: helps$ </h2>

You might be interested in

Y’all I need help fast

vitfil [10]

Answer:

All Real Numbers, this is because it has infinitely MANY solutions.

Step-by-step explanation:

7 0

2 years ago

Und your answers to the near<br> 6(7y + 8) = 22

Vladimir [108]

Answer:

y=⁻ $\\\frac{13}{21}$ should be your answer in decimal form its y=-0.619047

Step-by-step explanation:

4 0

2 years ago

Please help me find the slope thanks

dlinn [17]

The slope should be 3/10.

4 0

2 years ago

Solve for x in the given interval.<br><br> sec x= -2√3/3, for π/2 ≤x≤π

drek231 [11]

Answer:

b. $x=\frac{5\pi}{6}$

Step-by-step explanation:

The given function is

$\sec x=-\frac{2\sqrt{3} }{3},\:\:for\:\:\frac{\pi}{2}\le x \le \pi$

Recall that the reciprocal of the cosine ratio is the secant ratio.

This implies that;

$\frac{1}{\cos x}=-\frac{2\sqrt{3} }{3}$

$\Rightarrow \cos x=-\frac{3}{2\sqrt{3} }$

$\Rightarrow \cos x=-\frac{\sqrt{3}}{2}$

We take the inverse cosine of both sides to obtain;

$x=\cos^{-1}(-\frac{\sqrt{3}}{2})$

$x=\frac{5\pi}{6}$

4 0

2 years ago

PLEASE HELP!!! GEOMETRY<br> please

Cloud [144]

Nothing else is given, so for the two triangles to be congruent, the only possible proof is the ASA theorem.
first pairs of angles: 2x+7=x+21 => x=14
second pairs of angles: 8y-4=4y+28 =>y=8
The two triangles share the same side PR
Based on the Angle-Side-Angle Triangle Congruence theorem, these two triangles are congruent with x=14, y=8
(2x+7) +(8y-4) +Q=180 =>85

4 0

2 years ago