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guajiro [1.7K]
3 years ago
14

What is a rhombuses?​

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

Hey there! I hope this helps you. If you have any questions or concerns feel free to leave them in the comments so I can answer. Thank you!

A <u>rhombus </u>would be a flat shape that has <u>4 equal straight sides</u>. People also refer to it as a <u>parallelogram.</u>

<em />

<em>-All sides are equal</em>

<em>-Opposite sides parallel</em>

~I hope I helped you! :)~

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Find the volume of a pyramid with a square base, where the area of the base is 19.8 cm2 and the height of the pyramid is 13.9cm.
PilotLPTM [1.2K]

Answer:

91.7 cm^3

Step-by-step explanation:

Vol=\frac{1}{3} \times base area \times height=\frac{1}{3} \times 19.8 \times 13.9= 91.7 cm^{3}

7 0
3 years ago
What is the common ratio for 2,6,18
Dmitrij [34]

Answer:

3

Step-by-step explanation:

r=6/2=3

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Please solve this #33
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2 years ago
A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.
scZoUnD [109]

Answer: The required ratio will be

84:1034

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

2x=30\\\\x=\frac{30}{2}=15\ inches

So, Length of AD becomes

3x=3\times 15=45\ inches

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

\frac{30}{2}=15\ inches

So, Area of semicircle along AB and CD is given by

2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2

Radius of semicircle along AD is given by

\frac{45}{2}=22.5\ inches

Area of semicircle along AD and BC is given by

2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2

And the combined area of the semicircles is given by

\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2

Area of rectangle is given by

Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034

Hence, the required ratio will be

84:1034

8 0
3 years ago
Drinks at the fair cost 2.50$ use an equation to represent the relationship between the numbers of drinks bought ad the cost def
vodomira [7]
C=5/2*d where c-cost. d-drink
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3 years ago
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