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UkoKoshka [18]
3 years ago
13

What is the slope of this line?

Mathematics
1 answer:
Rasek [7]3 years ago
8 0

-1 will be the answer.

You might be interested in
During a musical an orchestra is playing. As the music plays, the volume changes in the beginning of the piece can be modeled by
sweet [91]

Hey Child.

The answer to this is 1 or 7:

To find the range for the number of measures played to satisfy our solution, we must solve for x using s = 80.

Next, we subtract 50 from both sides of the equation.

Next, we divide both sides of the equation by 10

Next, to eliminate the absolute value bars, we will add a ± sign in front of our s value, 3.

Finally, we add 4 to both sides of our equation giving us 4 ± 3 = x

Separating this into two equations, we get 4 - 3 = x and 4 + 3 = x

Therefore, x, the number of measures of music played, must be either 1 or 7.

Hope It Helped!~

\frac{JesusLoveMeAlways}{}

<h3>¬❤♪❤♪¬</h3>
4 0
4 years ago
Calculate the average rate of change of f(x) = x2 4 - 5 for 3 ≤ x ≤ 5.
pogonyaev

Answer:

8

Step-by-step explanation:

Substitute the equation and values into the average rate of change formula.

3 0
4 years ago
The price of one sack of rice is Rs. 1,850.if wages charge Rs. 70 was added, find it price.​
Yuliya22 [10]

Answer:

The total price of the Rice sack is Rs 1920.

Step-by-step explanation:

The price of 1 sack of rice = Rs. 1,850

Wages Charge = Rs. 70

Now, the total price = Price of the Rice + Wages Charge

= Rs. 1,850 + Rs. 70

= Rs. 1920

or,  the total price = Rs. 1920

Hence, the total price of the Rice sack is Rs 1920.

8 0
3 years ago
If is parallel to , which statement must be true?
Igoryamba
I’m pretty sure it’s d
6 0
3 years ago
Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
3 years ago
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