i believe it is 645, 500 !
Let hamburger = fries + 50
2hamburger + 3fries = 1700 **Given**
2(fries+50) + 3fries = 1700
2fries + 100 + 3fries = 1700
5fries = 1600
fries = 320
hamburger = 320 + 50
hamburger = 370 cal
1) Data:
Meal calories consumed
Breakfast 400 cal
Lunch 350 cal
Dinner x
------------------
Total 400 + 350 + x = 750 + x
2) Equation: <span>
She consumes 2/3 of her daily calories at dinner => (2/3)[750+x] = x
3) Analyze each statement:
</span><span>a) Lena
consumed 1500 cal at dinner.
Solve the equation to find if the statement is true:
</span>
<span><span>(2/3)[750+x] = x</span>
2(750+x) = 3x
1500 + 2x = 3x
1500 = 3x - 2x
x = 1500
Conclusión: TRUE stament.
b) Do you equation 2/3 (x+400+350)=x can be
used to model the situation.
That is the same equation that I found above.
Conclusion: TRUE statement
c) Lena consumed 500 cal at dinner.
She consumed (2/3) * 1500 = 500 cal
Conclusion: TRUE statement
d) Lena
consumed 1000 cal at dinner.
No, we calculated that she consumed 500 cal at dinner.
Conclusion: FALSE statement
e) The equation 2/3(x)=x(400+350) can be used
to model the situation.
No: (2/3) x = 500 and x(400+350) = 500*750 = 375,00, which are not equal.
Conclusion: FALSE statement.
f) The equation 2/3x(400+350)=x Can’t be used to
model the situation
No: in that equation the variable x cancels out because it appears a factor at both sides.
</span>Conclusion: TRUE statement
Answer: B,C,D,E,G
Step-by-step explanation:
Answer:
y = 5/3x - 7
Step-by-step explanation:
5x + 3y = -21
5x - 3y = -21
-3y = -5x - 21
-y = -5/3x + 7
y = 5/3x - 7
Kayden Kohl
8th Grade Student
