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lianna [129]
3 years ago
8

PLEASE HELP PLEASE PLEASE PLEASE

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

33

Step-by-step explanation:

The product of the secant segment lengths is a constant.

... TC×CV = UC×CW

... 14(2x+2) = 12(2x+5) . . . . substitute the values from the diagram

... 28x +28 = 24x +60 . . . . eliminate parentheses

... 4x = 32 . . . . . . . . . . . . . . add -28-24x

... x = 8 . . . . . . . . . . . . . . . . divide by 4

UW = 12 + 2x + 5 = 17+2·8 . . . . UW = UC + CW

UW = 33

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7 0
2 years ago
What is the value of e in e^x
Nookie1986 [14]

Answer

approximately 2.718

Step-by-step explanation

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7 0
3 years ago
3c-2(c+10)=7c-5(c+2)
jeka94

Answer: C= -10

Step-by-step explanation: First step: simplify both sides of the equation

3c−2(c+10)=7c−5(c+2)

3c+(−2)(c)+(−2)(10)=7c+(−5)(c)+(−5)(2) (Distribute)

3c+−2c+−20=7c+−5c+−10

(3c+−2c)+(−20)=(7c+−5c)+(−10) (Combine Like Terms)

c + -20 = 2c - 10

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Step 2: Subtract 2c from both sides

c - 20 - 2c = 2c -10 - 2c

−c−20=−10

Step 3: Add 20 to both sides

−c−20+20=−10+20

−c=10

Step 4: Divide both sides by -1

-c/-1 = 10/-1

C=-10

   

6 0
3 years ago
Each calendar will sell for 5 each. Write an equation to model the total income, y, for selling x calendars
OleMash [197]

Answer:

y = 5x

Step-by-step explanation:

If each calendar, <em>x</em>,  sells for $5 each, you would multiply 5·x because $5 is how much you earn per calender. Therefore, your total income would be 5 times the number of calendars you sell, or in equation "language", y = 5x

3 0
2 years ago
Pre-Calc Help:
jasenka [17]
The answer is 8 because you have 3 /4
6 0
3 years ago
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