Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
Answer:
−1.01
Step-by-step explanation:
Simplify the expression!
Simplify both sides to compare:
6^2 - 2^2 = 36-4 = 32
4(6+2) = 4 x 8 = 32
they are equal to each other.
Answer: B. =
Answer:
yes you are correct your very smart
Step-by-step explanation:
Answer:
1 line is determined by 2 points.
Step-by-step explanation:
