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Mrrafil [7]
3 years ago
10

A pole that is 2.5 m tall casts a shadow that is 1.07 m long. At the same time, a nearby tower casts a shadow that is

Mathematics
1 answer:
valkas [14]3 years ago
7 0

Answer:

The tower is 61.65 meters tall.

Step-by-step explanation:

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Question 4
lawyer [7]

Answer:

18ft

Step-by-step explanation:

L = length

W = width

l = w + 2ft ; because the is 2 ft longer than width

The area of a rectangle is lw

You can take the first equation ( l = w + 2 ) and plug it in lw

like this: lw ---> (w+2)w = w^2+2w

then from the question you get: w^2+2w=19.25

you use the quadratic formula and get w = 3.5

then from the first equation, you get l = 3.5+ 2 so the length is 5.5

lastly, you use the perimeter formula: 2(l+w) so 2(9) = 18

so 18ft

3 0
3 years ago
The volume of a sphere can be determined by the formula V = 4/3 πr^3, where r is the radius. What is the volume of a sphere with
allochka39001 [22]

Answer:

V = \frac{99}{7} x^{9}y^{-6}

Step-by-step explanation:

Given

V = \frac{4}{3}\pi r^3

Required

Find V when

r = \frac{3}{2}x^3y^{-2

Substitute \frac{3}{2}x^3y^{-2 for r in V = \frac{4}{3}\pi r^3

V = \frac{4}{3}\pi * (\frac{3}{2}x^3y^{-2})^3

Open bracket

V = \frac{4}{3}\pi * \frac{3}{2}^3 * x^{3*3}y^{-2*3}

V = \frac{4}{3}\pi * \frac{27}{8} * x^{9}y^{-6}

Simplify the fractions

V = \pi * \frac{9}{2} * x^{9}y^{-6}

Let

\pi = \frac{22}{7}

So:

V = \frac{22}{7}  * \frac{9}{2} * x^{9}y^{-6}

V = \frac{11}{7} * \frac{9}{1} * x^{9}y^{-6}

V = \frac{99}{7}   * x^{9}y^{-6}

V = \frac{99}{7} x^{9}y^{-6}

6 0
3 years ago
Caroline delivers flowers and earns $1.25 for each rose and $0.75 for each daisy. What is her total pay for a week in which she
SCORPION-xisa [38]

Answer:

She will be paid $684

6 0
3 years ago
20 POINTS AND WILL MAKE BRAINLIEST IF YOU HELP ME
Phantasy [73]
Give us more detail on what this is more about
7 0
3 years ago
Which inequality is represented by the graph y>-2/3x+1 y<-2/3x+1 y<-3/2x+1 y>-3/2x+1
soldi70 [24.7K]

Answer:

the 3rd one is the graph answer

6 0
3 years ago
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