2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer:x + y = 54
x - y = 10
Add them to get: 2x = 64
x = 32
and plugging in x = 32 to either equation: y = 22
Ans: the numbers are 22 and 32
Step-by-step explanation:
Answer: 90 degrees clockwise
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
The terms are separated by the "-"
