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Liono4ka [1.6K]
3 years ago
10

All help is much appreciated please and thank you

Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0
Once again similar traingles.

With same ratioes as before.

RS/RT = RV/RU=SV/TU = 1/2

\frac{w - 41}{w}  =  \frac{1}{2}  \\ 2w - 82 = w \\ w = 81 \: units
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Find each product mentally. show the steps you used.7 × 2.9
JulijaS [17]
Answer is 20.3 and the steps are:
1.) 7 x 9 = 63 move the six over the 2 leave the 3 down
2.) 7 x 2 = 14
3.) 14 + 6 = 20
4.) you have 203 but must bring the decimal down and it makes it: 20.3
I hope I helped and if you're confused please ask questions
6 0
3 years ago
Given a dilation with the origin O (0, 0), by observation determine the scale factor "K."
BaLLatris [955]
When the dilation is about the origin, the scale factor multiplies every coordinate. That is (considering the x-coordinate) ...
  6·k = 3
  k = 3/6 = 1/2

The appropriate choice is
  1. 1/2
4 0
3 years ago
Read 2 more answers
What is 283+t 748-235+7493-7
WARRIOR [948]

Answer:

t^748+7534

Step-by-step explanation:


8 0
3 years ago
Find the Two Values that x can have if X^2 -10=26​
Zolol [24]

Answer:

x1= -6 x2=6

Step-by-step explanation:

x^2-10 = 26

x^2 = 26 +10

x^2 = 36

x = sqrt(36)

x = -6 or x = 6 because both 6 and -6 squared are equal to 36

3 0
2 years ago
Read 2 more answers
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
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