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3 years ago

What precent of 44 is 11 helllllllllllllllllllllllllllllllllllllllllllllllllllllllllpplz

Mathematics

2 answers:

olganol [36]3 years ago

5 0

Answer:

25.

Step-by-step explanation:

44:11*100 = 25

aliya0001 [1]3 years ago

3 0

Answer:

25%

Step-by-step explanation:

Of means multiply and is means equals

P *44 =11

Divide each side by 44

P *44/44=11/44

P = 1/4

P = .25

Change from decimal form to percent form by multiplying by 100

P = 25%

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In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalizat

Viktor [21]

Answer:

Sample mean for solution 1: 19.27; sample mean for solution 2: 10.32

Step-by-step explanation:

To find the sample mean, find the sum of the data values and divide by the sample size.

For solution 1, the sum is given by:

9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7

The sample size is 10; this gives us

192.7/10 = 19.27

For solution 2, the sum is given by:

10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2

The sample size is 10, this gives us

103.2/10 = 10.32

6 0

3 years ago

jason made 42 christmas cookies he gave half of them to his teacher he ate 1 third of them then gave 8 to his little sister how

ch4aika [34]

Answer:

and why did teacher ate it

6 0

3 years ago

The life, in years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o

Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

$\bf P(X$

So, the probability that a switch fails in the first year is

$\bf P(X$

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and

$\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}$

where

$\bf \binom{100}{k}$ equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

$\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999$

3 0

3 years ago

Which of the following statements are true? Select all that apply.

Tom [10]

Answer: The statements in options 2 and 4 are true.

Explanation:

The LCM of two numbers is the smallest number that is multiple of both numbers.

The factor of 8 and 12 are,

$8=2\times 2\times 2$

$12=2\times 2\times 3$

Since 2 and 2 are common in both but 2 and 3 are not same, therefore the L.C.M. of 8 and 12 is,

$L.C.M.(8,12)=2\times 2\times 2\times 3=24$

Therefore the statement in option 1 is incorrect.

The factor of 6 and 9 are,

$6=2\times 3$

$9=3\times 3$

Since 3 is common in both but 2 and 3 are not same, therefore the L.C.M. of 6 and 9 is,

$L.C.M.(6,9)=2\times 3\times 3=18$

Therefore the statement in option 2 is correct.

The factor of 11 and 4 are,

$11=1\times 11$

$4=2\times 2$

Since all factor are different, therefore the L.C.M. of 11 and 4 is,

$L.C.M.(11,4)=1\times 11\times 2\times 2=44$

Therefore the statement in option 3 is incorrect.

The factor of 9 and 10 are,

$9=1\times 9$

$10=2\times 5$

Since all factor are different, therefore the L.C.M. of 9 and 10 is,

$L.C.M.(9,10)=1\times 9\times 2\times 5=90$

Therefore the statement in option 4 is correct.

4 0

3 years ago

Will mark you BRAINLIEST!

valentinak56 [21]

Answer:

x = 9/8

Step-by-step explanation:

The triangles are similar so we can use ratios to solve

AB BC

---- = -----------

AD ED

x 1

---- = -----------

x+9 9

Using cross products

9*x = 1(x+9)

9x = x+9

Subtract x from each side

9x-x = x+9-x

8x = 9

Divide by 8

8x/8 = 9/8

x = 9/8

7 0

3 years ago

Read 2 more answers