This can be done using synthetic division.
1 -2 -14 -5
-3 -3 15 -3
___________
1 -5 1 -8
v^2 - 5v + 1 remainder -8
OR
v^2 - 5v + 1 -8/(v + 3)
Answer:
C. WP WB, WC, PB, PC, BC
Step-by-step explanation:
<em>List the possible combinations. (With no duplicates)</em>
WP, WB, WC
PB, PC
BC
<em>Now check your options for the answer with the combinations you had.</em>
<em>That is your answer.</em>
) Using formula for cicumference.
Circumference = Pi * diameter
Circumference = Pi * 80m
Circumference = 251.2m.
Total inside length of the curved ends.
2)Total distance round inside of track =
2(125) + 251.2m
= 250 + 251.2
= 501.2m
3) Area of circular ends =
Pi*r^2
= Pi*40^2
= 5024m^2
Area of central area (rectangle)
length * width
125m * 80m
= 10,000m^2
Total area inside track =
5,024m^2 + 10,000m^2
= 15,024m^2
Hope this helps.
:-)
Answer:
51.9
8.9
78.5
8.8
Explanation:
You round up if the number to the right is 5 or greater.
So, apply this to the numbers and the 8 in A rounds up, going to a 51.9.
The 9 does not round up because of the one.
The 5 also does not round up because of the 2.
The 7 does round up because of the 6.
Answer:
1344 ft^2
Step-by-step explanation:
From the picture we can see that 4w = 3l, which means that l = (4/3)w. Since w = 12 ft, l = (4/3)(12 ft) = 16 ft. Then the total area of the floor is
(length of floor)(width of floor) = (48 ft)(12 ft + 16 ft) = 1344 ft^2
