Answer:
$110.37
Step-by-step explanation:
Assuming the monthly payment is made at the beginning of the month, the formula for the monthly payment P that gives future value A will be ...
... A = P(1+r/12)((1+r/12)^(nt) -1)/(r/12) . . . . n=compoundings/year, t=years
... 14000 = P(1+.11/12)((1+.11/12)^(12·7) -1)/(.11/12)
... 14000 = P(12.11)((1+.11/12)^84 -1)/0.11 ≈ P·126.84714 . . . . fill in the given values
... P = 14000/126.84714 = 110.37 . . . . . divide by the coefficient of P
They should deposit $110.37 at the beginning of each month.
Answer:
6 years
Step-by-step explanation:
First, you need to write an equation for this problem. I'll write it in slope intercept:
y = mx + b
where m is the slope and b is the y-intercept
To find m, do (change in y/change in x):
using (2, 59000) and (5, 72500),
(72500 - 59000) / (5 - 2)
= 13500 / 3
= 4500
So we have y = 4500x + b
To find b, plug in one of the points into the equation with the slope:
using (2, 59000),
y = 4500x + b
59000 = 4500(2) + b
59000 = 9000 + b
50000 = b
So now you have an equation: y = 4500x + 50000. Now that there is an equation, just insert the given y-value and solve:
when y = 77000
y = 4500n + 50000
= 77000 = 4500x + 50000
= 27000 = 4500x
= 6 = x
So, when Claire's Salary is 77000, her number of years at the company is 6.
8t+32 is one expression equivalent to that.
Answer:
thr answers are A and D of the question
