All categories

3 years ago

Anyone please help me

Mathematics

2 answers:

Ulleksa [173]3 years ago

8 0

Answer:

Step-by-step explanation:

The perpendicular equation can be found by getting the reciprocal of the slope then multiplying it by -1. The slope is the "m" value of y=mx+b; in this case, the slope is $\frac{2}{5}$ .

To find out if it is C or D, you plug in the x value given in the equation (2) and see if it equals the y value given in the equation (-2). C is incorrect, which means that D is correct.

ra1l [238]3 years ago

3 0

Answer:

The answer is D

Step-by-step explanation:

You might be interested in

Find the missing value (5,y) and (-3,2) ;m=2

Harlamova29_29 [7]

Answer:

answer is 5

Step-by-step explanation:

5 0

3 years ago

Luther evaluated 2^3 as 9 and wade evaluated 3^2 as 9 are both students correct?

MatroZZZ [7]

Answer:

Step-by-step explanation:

Luther is incorrect. 2 x 2= 4 x 2 = 8 (not 9)

1 2 3

6 0

3 years ago

Read 2 more answers

How do i do 3 part a ?

WINSTONCH [101]

In general the binomial expansion is

$(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0$

So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

$(-3x+1)^{11} = 1 (-3x)^0 1^{11} + 11(-3x)^{1} 1^{10} + 55 (-3x)^2 1^{9} + 165 (-3x)^3 1^8 + ...$

$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

6 0

3 years ago

In ΔRST, r = 210 cm, s = 500 cm and t=560 cm. Find the measure of ∠T to the nearest 10th of a degree.

Virty [35]

Answer:

95.3

Step-by-step explanation:

7 0

3 years ago

Solve and show your work for each question...

satela [25.4K]

$0.\overline{36} = \dfrac{36-0}{99} = \dfrac{36}{99} = \dfrac{4}{11}\\\\\\0.3\overline{6}= \dfrac{36-3}{90} = \dfrac{33}{90} = \dfrac{11}{30}\\\\\\0.36 = \dfrac{36}{100} = \dfrac{9}{25}$

4 0

2 years ago