Answer:
b) One sample z-test for means
Step-by-step explanation:
Normal Distribution
we have μ₀ (population mean from previous studies)
sample size n = 100
standar deviation of population σ = 0.75
And it was determined from sample, that μ = 5 : so we want to know if, at some significance level that value (which is smaller than population mean ) could help in relation to decide about rejecting hypothesis H₀
We should use a z one tail-test for means (left tail)
5.6 gallons of paint are needed to cover 1,960 square feet.
two gallons are needed for 700, so divide 700 by 2 to get square feet per gallon.
then divide 1,960 by 350 to get the gallons of paint needed
5.6 gallons
Hope this helps!
A = P(1+r/12)^12t, where A = amount after two years, P = Initial amount = $1000, r =apr = 4.2% = 0.042, t = period = 2 years
Then,
A = 1000 (1+0.042/12)^12*2 = $1087.47
Answer:
I think it is $139.30. But I'm not 100% sure
Step-by-step explanation:
Answer:
0.57142857142
Step-by-step explanation: