Question

Can someone help with this

Answer 1

Draw a triangle then use pythagoras theorem

Answer 2

Answer:

$GH=2\sqrt{10}$

Step-by-step explanation:

Considering each is square is 1x1.

We have the points G(-2, -3) and H(0, 3).

Using the distance formula:

$d=\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$d=\sqrt{(-2 - 0)^2 + (-3 - 3)^2}$

$d=\sqrt{(-2 )^2 + (-6)^2}$

$d=\sqrt{4 +36}$

$d=\sqrt{40}=2\sqrt{10}$

Also, using the Pythagorean theorem:

$a^2+b^2=c^2$

$2^2+6^2=c^2$

$4+36=c^2$

$c=GH=\sqrt{40}=2\sqrt{10}$