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VMariaS [17]
3 years ago
15

Compare the given dimensions of four triangles. Which triangle is possible to construct? side lengths of 5 ft, 12 ft, and 13 ft

side lengths of 2 ft, 11 ft, and 15 ft side lengths of 3 ft, 7 ft, and 11 ft side lengths of 4 ft, 8 ft, and 15 ft
Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0
(5,12,13) is a right triangle and can be constructed.
All the others do not satisfy the triangle inequality, i.e. the sum of two short sides must exceed the long side in order for the triangle to be constructed.
Examples:
2+11<15, so no
3+7<11, so no
4+8<15, so no
but 5+12>13  so yes, it can be constructed.
serg [7]3 years ago
4 0

Answer:

a

Step-by-step explanation:

just know this is 100% correct

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Find the inner product for (5,-1)*(-3,6) and state whether the vectors are perpendicular. a. 21; no c. -21; no b. 21; yes d. -21
nataly862011 [7]

Answer:

c

Step-by-step explanation:

If the dot product of the vectors is zero then they are perpendicular

(5, - 1) • (- 3, 6)

= (5 × - 3) + (- 1 × 6) = - 15 + (- 6) = - 15 - 6 = - 21 ≠ 0

Since product is not zero vectors are not perpendicular

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3 0
3 years ago
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Help pls pls I really need help
Misha Larkins [42]
C is correct bc if you add 10 to x you get the value of y
5 0
3 years ago
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Given the choice between receiving $1.000.000 in one month or a single penny-doubled everyday for the period of one month; which
Margarita [4]

Answer:

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Step-by-step explanation:


3 0
3 years ago
Write 14/√2 + √50 in the form b√2 where b is an integer.
kifflom [539]

Answer:

12 \sqrt{2}

Step-by-step explanation:

Taking the terms one at a time,

\frac{14}{ \sqrt{2} }  \\   \frac{14 *  \sqrt{2} }{ \sqrt{2} *  \sqrt{2}  }  \\   \frac{14  \sqrt{2} }{2}  \\  7 \sqrt{2}

\sqrt{50} \\  \sqrt{25 * 2} \\  \sqrt{25}*  \sqrt{2}    \\ 5 *  \sqrt{2}   \\ 5 \sqrt{2}

Adding the terms, you have;

7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}

Hope it helps!

I'm out!

3 0
3 years ago
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