Answer: x + 2
Step-by-step explanation:
Given the equation to solve by long division :
Divide x² - x - 6 by x - 3
x in the divisor is used to divide the x² in the Dividend to obtain a value of x as the quotient. The quotient value is multiplied by each value in the Dividend and so on.
This steps taken obtain the quotient is clearly shown in the picture attached.
Answer:
trophospe we it's where planes and aircraft fly
Answer:
You know if it is day time or night time
Step-by-step explanation:
<h3><u>The value of the smaller number is 31.</u></h3><h3><u>The value of the larger number is 43.</u></h3>
y = 12 + x
y + x = 74
Since we have a value for y, we can plug it into the second equation
12 + x + x = 74
Subtract 12 from both sides.
x + x = 62
Combine like terms.
2x = 62
Divide both sides by 2.
x = 31
Now that we have a value of x, we can plug it into the original equation to get a value for y.
y = 12 + 31
y = 43
To find the 20th term in this sequence, we can simply keep on adding the common difference all the way until we get up to the 20th term.
The common difference is the number that we are adding or subtracting to reach the next term in the sequence.
Notice that the difference between 15 and 12 is 3.
In other words, 12 + 3 = 15.
That 3 that we are adding is our common difference.
So we know that our first term is 12.
Now we can continue the sequence.
12 ⇒ <em>1st term</em>
15 ⇒ <em>2nd term</em>
18 ⇒ <em>3rd term</em>
21 ⇒ <em>4th term</em>
24 ⇒ <em>5th term</em>
27 ⇒ <em>6th term</em>
30 ⇒ <em>7th term</em>
33 ⇒ <em>8th term</em>
36 ⇒ <em>9th term</em>
39 ⇒ <em>10th term</em>
42 ⇒ <em>11th term</em>
45 ⇒ <em>12th term</em>
48 ⇒ <em>13th term</em>
51 ⇒ <em>14th term</em>
54 ⇒ <em>15th term</em>
57 ⇒ <em>16th term</em>
60 ⇒ <em>17th term</em>
63 ⇒ <em>18th term</em>
66 ⇒ <em>19th term</em>
<u>69 ⇒ </u><u><em>20th term</em></u>
<u><em></em></u>
This means that the 20th term of this arithemtic sequence is 69.
