Answer:
Step-by-step explanation:
For Question 3, we are simply taking an input for the function, as a value of x and solving the equation. For part a, we substitute 3/14 into the first function, and solve it:
f(x) = 7(3/14) + 2
f(x) = 21/14 + 2
f(x) = 49/14
f(x) = 7/2
For part b, we take the input of -3 into the second function and solve the equation:
h(x) = 4(-3)^2
h(x) = 4(9)
h(x) = 36
For Question 4, we are simply solving this equation by isolating the x variable. First, we simplify the equation to 4-5x+15+2x = -2 and simplify this again to -3x+19 = -2. Now, we can subtract 19 from both sides of the equation to get -3x = -21. Lastly, we isolate the x variable by dividing both sides of this equation by -3, to get x = 7.
22, i think because 3 times 3= 9, and 9 times 3 minus 5= 22
Answer:
Para el CO₂ sabemos que:
densidad = 0,001976 g/cm³
Sabemos que:
densidad = masa/volumen
Entonces, si tenemos una masa de 28 g, podemos escribir:
volumen = masa/densidad
volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3
Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.
Carbono: tiene una masa molar de 12 g/mol
Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)
entonces la masa molar va a ser:
masa molar = 12g/mol + 2*16g/mol = 44 g/mol
Es decir, un mol de CO₂, pesa 44 gramos.
