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postnew [5]
2 years ago
12

What is 2x-9=5x+12 with the step by step

Mathematics
2 answers:
snow_lady [41]2 years ago
6 0

Answer:

2x - 9 = 5x + 12 \\  - 3x = 21 \\   x =  - 7

Step-by-step explanation:

<em>x</em><em> </em><em>=</em><em> </em><em>-7</em>

jenyasd209 [6]2 years ago
3 0

Answer:

x = -7

Step-by-step explanation:

Please view the detailed answer in the image attached

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3 years ago
Seven years ago, lan purchased a $265,000 home with a 30-year mortgage at 3.5%. Having recently lost his job, he can no longer a
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3 years ago
Simplify the following expression. show your work.<br> (-y + 5.3) + (7.2y - 9)
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Answer:

6.2y - 3.7

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6 0
2 years ago
A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and
goldfiish [28.3K]

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(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

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(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}

Solve for S(t):

\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}

e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}

The left side is the derivative of a product:

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e^{t/800}S(t)=64e^{t/800}+C

S(t)=64+Ce^{-t/800}

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0=64+C\impleis C=-64

and so (b) the amount of sugar in the tank at time t is

S(t)=64\left(1-e^{-t/800}\right)

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7 0
3 years ago
(1.2x10^5)+(2.4x10^4) what is the sum
Harman [31]

Answer:

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