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2 years ago

5

Erin was able to map line segment \overline{AB}

1 answer:

horrorfan [7]2 years ago

6 0

Answer:

There is no error

Step-by-step explanation:

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What is the discount on a stethoscope that is marked down from $300 to $250

Aliun [14]

In percentage form it is 83.33% repeating, but in dollars it is $50

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2 years ago

Which expression is equivalent to 5/6 ÷ 4

Ronch [10]

Answer:

5/24 or in decimal form 0.2083

Hope this helped

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3 years ago

Find the equation of the line with Slope = 6 and passing through (5,38). Write your equation in the form y =mx+b

laiz [17]

Hello.

We have:

A point that the line passes through
The slope of the line

Plug the values into the Point-Slope Formula:

$\mathrm{y-y_1=m(x-x_1)}$

$\mathrm{y-38=6(x-5)}$

$\mathrm{y-38=6x-30}$

$\mathrm{y=6x-30+38}$

$\Large\boxed{\sf{ \ y=6x+8}}$

I hope it helps.

Have a nice day.

$\boxed{imperturbability}$

5 0

2 years ago

Read 2 more answers

Can some one explain please

inna [77]

What kind of question is this lol ? i don’t even understand it

7 0

2 years ago

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

7 0

2 years ago