Solve 4(c + 2) < 4c + 10.

Mathematics

1 answer:

Neporo4naja [7]3 years ago

4 0

4(c+2)<4c+10

4c+8<4c+10
-4c -4c
--------------------
8<10

Which gives you No Solution.

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Jean transformed a point by using the rule (x,y) (x-6, y+8). The image point is (–4, 1). Which point is the pre-image?

lubasha [3.4K]

For this case we have the following transformation:
$(x, y) (x-6, y + 8)
$
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$(-4, 1)
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How do you solve this

fiasKO [112]

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The best way is to make it one fraction.
Multiply by ((3x/3x) / (3x/3x)) to remove the other fractions.
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