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viktelen [127]
3 years ago
14

A jar of marbles contains 120 marbles the larger jar of marbles contains one and 56 times as many marbles how many marbles are i

n the larger jar
Mathematics
1 answer:
Papessa [141]3 years ago
6 0
I think it’s 6721 marbles in the larger jar.
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4x+6+ 3=-8<br> 2<br> What is x? <br> 4x+6 &lt;&lt;&lt;&lt;<br> 2 &lt;&lt;&lt; It’s a fraction
Andreas93 [3]

Answer:

-17/4

Step-by-step explanation:

4x+6+3=-8

4x+9=-8

-9 -9

4x=-17

÷4 ÷4

X=-17⁄4

6 0
2 years ago
Consider circle O. If AE = 7, EC = 2, and BE = 4, what is ED?
miv72 [106K]
The correct answer is 3.5

Two chords AC and BD are intersecting inside the circle. The Intersecting Chord Theorem states that when two chords intersect inside a circle, the products of their segments are equal.

Thus, for the given circle:
(AE) × (EC) = (BE) × (ED)

The lengths of the segments are
AE = 7
EC = 2
BE = 4
ED = ?

To solve for ED, we simply substitute the known values into the equation
ED =  \frac{7(2)}{4} = \frac{14}{4} = 3.5
6 0
3 years ago
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Brut [27]

Answer:

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3 0
2 years ago
Hello pls help I'm dumb thx it's pre calc
Bumek [7]
(f-g)(x)=f(x)-g(x)=
\frac{2x+6}{3x}-\frac{\sqrt{x}-8}{3x}=
\frac{2x+6-(\sqrt{x}-8)}{3x}=
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3 0
3 years ago
Find the area. The figure is not drawn to scale
poizon [28]

Answer:

96 square inches.

Step-by-step explanation:

From given picture we see that

BC=8 in

AD=10 in

Given that

AD=AB

Then AB=10 in

Apply Pythagorean theorem in triangle ABC to find AC

(hypotenuse)^2=(base)^2+(perpendicular)^2

(AB)^2=(BC)^2+(AC)^2

(10)^2=(8)^2+(AC)^2

100=64+(AC)^2

100-64=(AC)^2

36=(AC)^2

take square root

6=AC

Then area of triangle ABC =\frac{1}{2}\left(base\right)\left(altitude\right)

=\frac{1}{2}\left(8\right)\left(6\right)=24

There are total 4 congruent triangles.

Then total area of the given figure = 4(24)=96 square inches.

7 0
2 years ago
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