3 years ago

Simplify square root of x^2y^8

1 answer:

5 0

Sqrt x^2 y^8
The index is 2 so divide power by index
x y^4

You might be interested in

rosijanka [135]

The answer is J, 23/100.

3 0

4 years ago

sveticcg [70]

P = 2l + 2w
p-2w = 2l
p-2w/2 = l

Substitute the perimeter and you should be able to work it out

6 0

3 years ago

malfutka [58]

Answer: $f(x)=2x^2+5$

Step-by-step explanation:

First integrate f'(x) so we can find the funtion f(x):

$4\int\limits {x} \, dx =4[\frac{1}{2} x^2]=2x^2+C=f(x)$

The initial conditions say that when x = 0, the function equals 5. Let's write that down:

$f(0)=5=2(0^2)+C=C$

Therefore, the integration constant 'C' must equal 5. This means that our function is:

$f(x)=2x^2+5$

6 0

2 years ago

Inga [223]

I say it would be true

4 0

4 years ago

Travka [436]

Answer:

Step-by-step explanation:

If this were a right triangle we would assume the Pythagorean Theorem to prove it

$a^{2} +b^{2} =c^{2}$

$7^{2} +8^{2} =9.2^{2}$

this gives us

49+64=84.64

this is 143=84.64 and therefore not equal and not a right triangle

7 0

3 years ago