What is the nuclear binding energy for uranium-238 in joules? Assume the following:. Mass defect = 3.2008 x 10-27 kilograms. Use

Question

alexandr1967 [171]

3 years ago

7

What is the nuclear binding energy for uranium-238 in joules? Assume the following:. Mass defect = 3.2008 x 10-27 kilograms. Use

E = mc2, with c = (3 x 108 m/s)2 Select one of the options below as your answer:A. 0.28807 x 10-12 joules B. 2.8807 x 10-12 joules C. 2.8807 x 10-10 joules D. 2.8807 x 10-8 joules E. 3.2008 x 1027 joules

Chemistry

2 answers:

Arte-miy333 [17] · Answer 1 · 2022-06-30T14:10:18+03:00

The correct answer is (C) 2.8807 x 10^-10

The explanation:

According to this formula:

E = MC^2

when E is the nuclear binding energy

and M is the mass defect = 3.2008 x 10^-27 Kg

and C is the speed of light = 3 x 10^8 m/s^2

so, by substitution:

∴ E = 3.2008 x 10^-27 * (3 x 10^8 )^2

= 2.8807 x 10^-10

Amiraneli [1.4K] · Answer 2 · 2022-06-30T15:33:42+03:00

We are given with a mass defect and asked to compute the nuclear binding energy for the element- uranium 238. The formula to be used is E = m c^2 where m is the mass defect, c is the speed of light. Substituting these data, the nuclear binding energy, E is equal to C. 2.8807x10^-10 joules.