Answer:
I think B would be alcohol but A I'm not to sure
The amount (in pounds) the gasoline tank will hold when full is 153.76 lb
<h3>What is density? </h3>
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
<h3>How to convert gallon to milliliters </h3>
1 gallon = 3785.412 mL
Therefore,
25 gallon = 25 × 3785.412
25 gallon = 94635.3 mL
<h3>How to determine the mass </h3>
- Density = 0.737 g/mL
- Volume = 94635.3 mL
- Mass =?
Mass = Density × Volume
Mass = 0.737 × 94635.3
Mass = 69746.2161 g
<h3>How to convert grams to pounds </h3>
453.592 g = 1 lb
Therefore,
69746.2161 g = 69746.2161 / 453.592
69746.2161 g = 153.76 lb
Learn more about density:
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Answer:
An ion is charged because the number of electrons does not equal the amount of particles.
Explanation:
Can be positive (meaning more protons than electrons) and it can be negatively charged (meaning there are more electrons than protons).
Hope this helps!
Answer:
An insulated beaker with negligible mass contains liquid water with a mass of 0.205kg and a temperature of 79.9 °C How much ice at a temperature of −17.5 °C must be dropped into the water so that the final temperature of the system will be 31.0 °C? Take the specific heat for liquid water to be 4190J/Kg.K, the specific heat for ice to be 2100J/Kg.K, and the heat of fusion for water to be 334000J/kg.
The answer to the above question is
Therefore 0.1133 kg ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C
Explanation:
To solve this we proceed by finding the heat reaquired to raise the temperature of the water to 31.0 C from 79.9 C then we use tht to calculate for the mass of ice as follows
ΔH = m×c×ΔT
= 0.205×4190×(79.9 -31.0) = 42002.655 J
Therefore fore the ice, we have
Total heat = mi×L + mi×ci×ΔTi = mi×334000 + mi × 2100 × (0 -−17.5) = 42002.655 J
370750×mi = 42002.655 J
or mi = 0.1133 kg
Therefore 0.1133 kg ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C
