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3 years ago

10

Suppose another class

1 answer:

juin [17]3 years ago

5 0

Answer:

26

Step-by-step explanation:

22*0.2=4.4

22+4.4=26.4

when you round you will get 26

(you should probably ask your teacher which way to round.)

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3 years ago

Answer please. Please

ioda

3y-10 is greater to or equal to 47 add 10 to each side. 3y is great than or equal to 37 Now divide 37 by 3 which gives you an answer of 12.33 I hope this helps you!

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4 years ago

Read 2 more answers

If explained perfectly, I will place you as Brainliest. Explain easily on how to find surfce area for a triangular prism. Also w

marshall27 [118]

Answer:

/\------------------------------\

a / \ \

/ \ \ (Im not an artist....)

/_____ \________________\

b c

(A x B / 2) + (A x B / 2) + (A x C) + (A x C) + ( B x C) + (B x C)

Step-by-step explanation:

8 0

3 years ago

Radhika borrowed Rs.12000 from her friends. Out of which Rs.4000 were borrowed at 18% and the remaining at 15% rate of interest

goldfiish [28.3K]

<u>Answer-</u>

The total interest after 3 years is Rs.5760 .

<u>Solution-</u>

Total money borrowed = Rs.12000

Out of those Rs.4000 is of 18% interest rate and remaining 12000-4000=8000 is of 15% interest rate.

$\text{Total interest}=\frac{P_1\times r_1\times t}{100}+\frac{P_2\times r_2\times t}{100}$

Where,

P₁ = principal amount = Rs.4000

P₂ = principal amount = Rs.8000

r₁ = rate of interest of P₁ = 18%

r₂ = rate of interest of P₂ = 15%

t = time period = 3 years

$\text{Total interest}=\frac{4000\times 18\times 3}{100}+\frac{8000\times 15\times 3}{100}=2160+3600=5760$

8 0

3 years ago

2. Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79. What did it cost 10 years ago? How long

Makovka662 [10]

Answer:

It cost $0.91 10 years ago.

It takes 10.24 years for the cost of bread to double.

Step-by-step explanation:

The equation for the price of bread after t years has the following format:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the current price, and r is the inflation rate, as a decimal.

If we want to find the price for example, 10 years ago, we find P(-10).

Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79.

This means that $r = 0.07, P(0) = 1.79$ . So

$P(t) = P(0)(1+r)^{t}$

$P(t) = 1.79(1+0.07)^{t}$

$P(t) = 1.79(1.07)^{t}$

What did it cost 10 years ago?

$P(-10) = 1.79(1.07)^{-10} = 0.91$

It cost $0.91 10 years ago.

How long before the cost of the bread doubles?

This is t for which P(t) = 2P(0) = 2*1.79. So

$P(t) = 1.79(1.07)^{t}$

$2*1.79 = 1.79(1.07)^{t}$

$(1.07)^{t} = 2$

$\log{(1.07)^{t}} = \log{2}$

$t\log{1.07} = \log{2}$

$t = \frac{\log{2}}{\log{1.07}}$

$t = 10.24$

It takes 10.24 years for the cost of bread to double.

5 0

3 years ago