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abruzzese [7]
3 years ago
7

How to add 12/36 +3/6

Mathematics
2 answers:
larisa86 [58]3 years ago
6 0
3/6*6/6=18/36+12/36=30/36 or 15/18 or 5/6
Rasek [7]3 years ago
5 0
Divide both answers first ie. 12/36= 1/3
3/6= 0.5
Then add them
Ie. 1/3+0.5=0.833333333 (3 is a recurring decimal)
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Write the equation of a line that is perpendicular to y =3x-2 and that passes through the point(-9,5)
Oduvanchick [21]

Answer:

y = -1/3x + 8

Step-by-step explanation:

If two lines are perpendicular, the signs of the slope must be opposite and the slopes are reciprocals.

(basically if one is say -2/3, the other is 3/2. just flip it upside down)

So this slope is 3, so the new slope should be -1/3

The equation is now y = -1/3x + b

To find b, substitute (-9,5) in the equation

y = -1/3x + b

5 = -1/3(9) + b

5 = -3 + b

8 = b

So the equation is y = -1/3x + b

7 0
4 years ago
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What is the height of a rectangular prism that has a volume 192 cubic feet and a base with an area of 48 square feet?
Westkost [7]

Answer:

A rectangular prism has 3 measurements: length (l), width (w), and height (h)

The volume of a rectangular prism has the formula: V=lwh

The area of the base of the rectangular prism is its length times its width; or

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So, the volume of the rectangular prism can be written as:

Volume = area of the base * height

Substitute in your numbers:

192=48*h

h=192/48

h=4

So the height is 4 feet

Step-by-step explanation: Hope this helps. :))

3 0
3 years ago
I need help ,, i don't understand !<br>​
otez555 [7]

Answer: B

Step-by-step explanation: The question is asking for the point greatly different from all the rest, the outlier. Point B is far away from the grouping of all the other points, making it the outlier.

7 0
3 years ago
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ladessa [460]

Answer:

113.44

Step-by-step explanation:

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Julli [10]

Answer:

It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.

Step-by-step explanation:

i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.

ii. Construct the radius to bisect the chord, dividing it into two equal parts.

Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.

The construction to the question is herewith attached to this answer for more clarifications.

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