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Vadim26 [7]
3 years ago
8

What is the remainder of the function f(x)=x^4-3x^3+7x-1 is divided by (x-2)

Mathematics
1 answer:
Basile [38]3 years ago
6 0
The answer would be B

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A student is trying to solve the set of two equations given below: Equation A: x + z = 6 Equation B: 3x + 2z = 1 Which of the fo
solong [7]
A) multiply equation A by -2 so you get -2x - 2z = -12 and then you can add both equations to eliminate z
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3 years ago
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Are the these expressions equivalent 6a + 12 and 3(3a + 4)
kow [346]

Answer:

No

Step-by-step explanation:

6a + 12  =? 3(3a + 4)

Distribute

6a+12 =? 3*3a + 3*4

6a+12 =? 9a +12

No

The expressions are not equivalent

5 0
3 years ago
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The number of pens used varies directly with the number of pieces of paper needed. If 12 pens are used when 40 pieces of paper a
svetlana [45]

Answer:


Step-by-step explanation:

Y=KX


P=KX

12=K40

12/40=K

.3=K

P=.3X

P=.3(240)

P=72

6 0
3 years ago
there are 6 twenty pound boxes and 8 sixty pound boxes of produce on a truck. how many pounds of produce are on the truck
Klio2033 [76]

6 *20 = 120

8 *60 = 480


120 + 480 = 600 pounds total

6 0
3 years ago
Which equation justifies why nine to the one third power equals the cube root of nine?
AVprozaik [17]

Answer:

nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine

Step-by-step explanation:

we know that

The <u><em>Power of a Power Property</em></u> , states that :To find a power of a power, multiply the exponents

so

(a^{b})^{c}=a^{b*c}

In this problem we have

9^{\frac{1}{3}} =\sqrt[3]{9}

Remember that

\sqrt[3]{9}=9^{\frac{1}{3}}

Raise to the third power

[9^{\frac{1}{3}}]^3

Applying the power of power property

9^{\frac{3}{3}}

9^{1}

9

therefore

nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine

8 0
3 years ago
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