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3 years ago

Eleven students are competing in an art contest. In how

Mathematics

1 answer:

KatRina [158]3 years ago

5 0

Hi there

I think I may have the answer for you!

<u>Answer:</u>

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A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.

Please make sure to check my answer and mark it/

Jake

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Pamela and Debbie are shelving books at a public library. Pamela shelves 26 books at a time, whereas Debbie shelves 7 at a time.

Ira Lisetskai [31]

If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182

The number of books that Pamela can shelf at a time = 26

The number of books that Debbie can shelf at a time = 7

If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is the least common multiple of 26 and 7

The Least common multiple of 26 and 7 = 182

Therefore, if both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182

Learn more on Least Common Multiple here: brainly.com/question/363238

8 0

2 years ago

The large and medium shapes are scale drawings of the smallest shape the scale factor from the large shape to the media shape is

vovangra [49]

Answer:

Step-by-step explanation:

Add 65+40 which is going to give you 105 then once you get 105 subtract 65-40 which is going to give you 25 the 105 is the total so the whole answer is 25

5 0

2 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

2 years ago

Leah just moved and she's looking for a new dance studio. She gets to list the price from tip top toes charges $300 for 12 class

SpyIntel [72]

If it’s by week then groovin and movin,but if it’s months tip toes

8 0

2 years ago

Mr johnson's students want to know his age. He tells them that this year his age is a multiple of 9, and next year it will be a

vladimir1956 [14]

Answer:

He is 27 years old.

Step-by-step explanation:

27 is a multiple of 9 (9 x 3)

28 comes after, and is a multiple of 4 (4 x 7)

Hope this answer helps you!! :)

8 0

2 years ago