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Kaylis [27]
2 years ago
8

Angeline bought s yards of satin fabric priced at $8.09 per yard, and c yards of cotton fabric priced at $3.79 per yard. What ex

pression could you use to determine the total cost of the fabric? If she bought 5 yards of satin fabric and 8 yards of cotton fabric, how much did Angeline spend in all?
Mathematics
1 answer:
Alik [6]2 years ago
3 0

Answer:

$70.77

Step-by-step explanation:

Cost of 's' yards of satin fabric= 8.09*s = 8.09s

Cost of 'c' yard of cotton fabric = 3.79 * c = 3.79c

Total cost of fabric = 8.09s + 3.79c

s = 5 yards ;  c = 8 yards

Plugin the value of s and c in expression,

8.09*5 + 3.79*8 = 40.45 + 30.32

                          = $ 70.77

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Answer:

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Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

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