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Amiraneli [1.4K]
3 years ago
13

So I'm stuck on a math problem. Given z=3 + 5i and w= -5 +I, evaluate z-w

Mathematics
1 answer:
skad [1K]3 years ago
7 0

Answer:

8 + 4i  

Step-by-step explanation:

Put corresponding terms above each other and subtract in the usual way.

    z =   3 + 5i

<u>     w = -5 +   i </u>

z - w =  8 + 4i: 3 - (-5} = 8; 5i - 1i = 4 i

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-4a = -2n + 2p, for a
Elena-2011 [213]

Answer:

the value of a is n+p/2......…...

5 0
2 years ago
I need very urgent help with this
Leto [7]

Answer:

-5, -2, -1, 2

Step-by-step explanation:

You can find the answer by trying the given possible answers out.

7 0
3 years ago
Consider the initial value function y given by
Nuetrik [128]

Answer:

y(s) = \frac{5s-53}{s^{2} - 10s  + 26}

we will compare the denominator to the form (s-a)^{2} +\beta ^{2}

s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}

comparing coefficients of terms in s

s^{2} : 1

s: -2a = -10

      a = -2/-10

      a = 1/5

constant: a^{2}+\beta ^{2} = 26

               (\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = A(s-a)+B((s-a)^{2} +\beta ^{2} )

we insert the values of a and β

  \\5s-53 = A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

<em>the constants are</em>

<em>a = 0.2</em>

<em>β = 5.09</em>

<em>A  = 5.4</em>

<em>B = -2</em>

<em></em>

Step-by-step explanation:

  1. since the denominator has a complex root we compare with the standard form s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}
  2. Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
  3. substitute the values gotten into the function
  4. Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
  5. after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

3 0
3 years ago
Evaluate: 17 – 5(–3)<br> A.–28<br> B. 32<br> C. –8<br> D.–21
trapecia [35]
5 times -3 = -15
17 - (-15) = 32
B.32
8 0
3 years ago
Please help me with this question. <br>​
777dan777 [17]
There are 8 options in which it could land on and there are 3 A’s meaning the equation is 3/8 making the probability 37%
5 0
2 years ago
Read 2 more answers
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