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Setler79 [48]
3 years ago
7

The loan will be for $25900 over 5 years at 6.25% what will the interest be on the loan

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0
$809,375. You have to multiply all those three numbers
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The solution to 2x+8&gt;10 is x&lt;1 <br> true or false
Morgarella [4.7K]

Answer:

false

Step-by-step explanation:

correct me if this is wrong, but it's actually x>1

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The answer would be two
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3 years ago
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I need some help if you could
Fed [463]

Step-by-step explanation:

35A) arc AC = 360-(100+110+80)=

360-290 = 70°

35B) <em>L</em><em> </em>D = ½× 70 = 35°

35C) <em>L</em><em> </em>AEC = ½(100+70)=½×170= 85°

35D) <em>L</em><em> </em>P = ½(100-70) = ½×30 = 15°

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3 years ago
You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)
Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, v_1 = = 20 m./s

Velocity of the truck 2,v_2 = 35 m./s

1. Kinetic energy of the truck 1:\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules

Kinetic energy of the truck 2:\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height = mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0
4 years ago
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vovangra [49]

Answer:

9.4

Step-by-step explanation:

We can use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

5^2+8^2 = c^2

25 +64 = c^2

89 = c^2

Taking the square root of each side

sqrt(89) = sqrt(c^2)

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To the nearest tenth

9.4

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