3 are expected to have the condition.

The expected value is the found by multiplying the probability by the number in the sample:

(1/200)×600
= (1/200)×(600/1)
= (1×600)/(200×1)
= 600/200 = 3

3 0

2 years ago

For the rational expression 2x^2-7x-15/x^2-25, do both of the following,

Mrrafil [7]

Answer:

a. $\frac{2x + 3}{x+5}$

b. x ≠ -5 (Vertical asymptote) and x ≠ 5 (Hole)

Step-by-step explanation:

Factor the numerator (Grouping):

$2x^2 - 7x - 15$

Two numbers that multiply to -30 and add to -7 = -3 and 10

$[2x^2 - 10x] + [3x - 15]$

$(2x + 3)(x - 5)$

Factor the denominator (Difference of Two Squares):

$x^2 - 25$ = $(x +5)(x-5)$

Factored Expression:

(x - 5) can be factored out of top and bottom as a hole-

$\frac{(2x + 3)(x - 5)}{(x + 5)(x - 5)} = \frac{2x + 3}{x+5}$

Variable Restrictions:

Denominator ≠ 0

$x + 5 = 0\\x = -5$

Vertical asymptote at x = -5 ⇒ x ≠ -5

3 0

2 years ago

Solve the equation X/-2=5

Ipatiy [6.2K]

Answer:

$\boxed {x = -10}$

Step-by-step explanation:

Solve for the value of $x$ :

$\frac{x}{-2} = 5$

-Multiply both sides by $-2$

$x = 5 \times (-2)$

$\boxed {x = -10}$

So, therefore, value of $x$ is $-10$ .

7 0

3 years ago

The population p (in millions) of Italy from 1990 through 2008 can be approximated by the model p=56.8e^o.oo15t , where t repres

dimulka [17.4K]

As we already have the model that describes the change of the population in Italy in terms of the years that have elapsed, we only have to replace the conditions that are requested in that equation.

Therefore to find the population of Italy in the year 2000 (t = 10 years) substitute t = 10 in the equation and have:

$p = 56.8e^{0.0015*10}\\$