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Alexeev081 [22]
3 years ago
10

Find the area of a triangle with base of 10 inches and altitude to the base of 16 inches. 80 in² 135 in² 160 in²

Mathematics
2 answers:
kotykmax [81]3 years ago
7 0
10 × 16 = 160
160 / 2 = 80

Your answer would be 80<span>in²

Hope that helps!
</span>
Komok [63]3 years ago
3 0

Answer:

Option 1st is correct

area of a triangle is, 80 in²

Step-by-step explanation:

Area of triangle(A) is given by:

A = \frac{1}{2} b \cdot h

where,

b is the base

h is the height or altitude of the triangle respectively.

As per the statement:

Base of a triangle(b) = 10 inches and

Height = altitude(h) = 16 inches

Substitute these in [1] we get:

A = \frac{1}{2}(10) \cdot 16

⇒A = 5 \cdot 16 = 80in²

Therefore, the area of a triangle is, 80 in²

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The sum of the first 8 terms is 2.51 to the nearest hundredth

Step-by-step explanation:

In the geometric sequence there is a constant ratio between each two consecutive terms

The formula of the sum of n terms of a geometric sequence is:

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∴ n = 8

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Learn more:

You can learn more about the sequences in brainly.com/question/7221312

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<span>go tot he website of 
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It will help you understand the problem and give you the answer.
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