Answer:
A) 32.474 + 16.577
= 49.051
C) 19.213 + 4.578
= 23.791
Step-by-step explanation:
Place value may be defined as the positional system of a notation where the position of any number with reference to the decimal point determines the value of that number.
A) 32.474 + 16.577
= 49.051
B) 23.452 + 31.561
= 55.013
C) 19.213 + 4.578
= 23.791
D) 8.128 + 9.192
= 17.32
We have to find the expression which contains 1 in the thousandths place in the sum.
We know after the decimal point, the place value are designated as tenths, hundredths, thousandths, and so on.
Therefore, A). 49.051 and C). 23.791 has a place value of 1 in its thousandths place.
|3.5| = 3.5
Any negative or positive number will always have an absolute value that is positive.
For example, | -3.5| = 3.5
3.5 can also be expressed a fraction.
3.5 * 2/2 = 7/2
Jade hiked 1 1/4 miles on the trail. Gretta hiked 1 1/2 times as far on the trail as Jade.
Jade hiked = 
Gretta hiked = ![[tex]1\frac{1}{2} becomes \frac{3}{2}](https://tex.z-dn.net/?f=%5Btex%5D1%5Cfrac%7B1%7D%7B2%7D%20becomes%20%5Cfrac%7B3%7D%7B2%7D)
[/tex] times Jade hiked
So Gretta hiked = 
To multiply two fractions, we multiply numerator with numerator and denominator with denominator
Gretta hiked = 
miles
Answer: 1.013
Step-by-step explanation:
Given the following data :
X_______f___fx___fx²
1_______15__15___15
2______30__60__120
3______28__84__252
4______10__40___160
______ 83__199__547
Number that is 1.5 standard deviations below the mean :
Mean(m) :
Σfx /Σf
(15 + 30 + 28 + 10) / 83
= 199 / 83
= 2.3976
Standard deviation(s) :
Sqrt[(Σfx² - (Σfx)²/Σf) /Σf-1]
sqrt[(547 - (199)²/83) / 83 - 1]
sqrt[(547 - (39601/83) / 82]
sqrt[(547 - 477.12) / 82]
sqrt(0.8522)
Standard deviation = 0.9231
1.5 standard deviations below the mean:
Mean - 1.5(standard deviation)
2.3976 - 1.5(0.9231)
2.3976 -1.38465
= 1.01295
= 1.013
