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Pachacha [2.7K]
4 years ago
5

Can someone solve solve (-7) • (-4)

Mathematics
2 answers:
ale4655 [162]4 years ago
8 0

Answer:

28 is your answer

Step-by-step explanation:

Note that when you are multiplying (or dividing) two negative numbers, the answer would be positive.

Multiply as usual: -7 x -4 = 28

28 is your answer

~

marta [7]4 years ago
6 0

Answer:

28

Step-by-step explanation:


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Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
If f is translated 4 units down to create g, which function represents g? A. g(x) = f(x) - 4 B. g(x) = f(x - 4) C. g(x) = f(x +
dalvyx [7]

Answer:

g(x)=f(x)-4

Step-by-step explanation:

we are given

f is translated 4 units down to create g

we know that

whenever we translate any function by 'a' units down , we always subtract that function by 'a' units

Suppose, f(x) is translated down by 'a' units

so, we get

=f(x)-a

now, we have

f is translated 4 units down

so, we get

=f(x)-4

and it is creating g(x)

g(x)=f(x)-4


8 0
3 years ago
Which describes this transformation?
Svetllana [295]
I don’t know what you’re asking. Do you have a picture related to your question? :(
6 0
3 years ago
Kara has a piece of ribbon that is 24 inches long. She knows that this piece of ribbon is 2 feet long. Match the numbers that sh
Pani-rosa [81]

Answer:

12

Step-by-step explanation:

if there is 24 inches of ribbon it would be 12 because 12 inches = 1 foot

5 0
3 years ago
Kamala gave rs 1,50,000 to her friend.She gave currency notes of denomination Rs. 50,Rs.100,Rs.500 in the ratio 4:3:5.How many n
vivado [14]

Answer  

Find out the how many notes of each denomination did she give .

To prove

Let us assume that x be the scalar multiplication of the Rs 50, Rs100,Rs500 curreny notes.

As given

Kamala gave Rs 1,50,000 to her friend.

She gave currency notes of denomination Rs. 50,Rs.100,Rs.500 in the ratio 4:3:5.

Rs50 currency note gave in the denomination = 4x

Rs100 currency note gave in the denomination = 3x

Rs500 currency note gave in the denomination = 5x

than the equation becomes

4x + 3x + 5x = 150000

12x = 150000

x = \frac{150000}{12}

x = 12500

Thus

Rs50 currency note gave in the denomination = 4 × 12500

                                                                             = 50000

Rs100 currency note gave in the denomination = 3 × 12500

                                                                             = 37500

Rs500 currency note gave in the denomination = 5 × 12500

                                                                             = 62500


4 0
4 years ago
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