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Yanka [14]
3 years ago
6

Evaluate each expression if d=8, e = 3,f=4, and g=-1 Help!!!

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0

Step-by-step explanation:

1. 2(d+9)

2(8+9)

2(17)

=34

2. d÷4

8÷4

=2

3. ef÷4

(3×4)÷4

12÷4

=3

4. 4f+d

(4×4)+8

16+8 =24

5. (5d-25)÷5

((5×8)-25)÷5

(40-25)÷5

15÷5 = 3

6. d2+7

(8×8) +7

64+7

=71

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9. A band director wants to form a committee of 4 parents from a list of 45 band parents.
Alex73 [517]

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Part (A): The number of ways to select 12 jurors are 86493225.

Part (B): The number of ways to select 2 alternates are 306.

Part (C): Part (a) is an example of combination  and Part (a) is an example of permutation

Step-by-step explanation:

Consider the provided information.

A band director wants to form a committee of 4 parents from a list of 45 band parents.

Part (A):  How many different groups of 4 parents can the band director select?

Since order doesn't matter so we will use combination.

Use the formula for combination ^{n}C_{r}=\frac{n!}{r!(n-r)!}

Substitute n=45 and r=4 in above formula.

^{45}C_{4}=\frac{45!}{4!(45-4)!}

^{45}C_{4}=\frac{45!}{4!41!}

^{45}C_{4}=148995

Hence, the number of ways are 148995.

Part (B) How many different ways can the band director select 4 parents to serve in the band parents’ association as president, vice president, treasurer, and secretary?

Since the order matter so we will use permutation:

The formula for permutation is:  ^{n}P_{r}=\frac{n!}{(n-r)!}

Substitute n=45 and r=4 in above formula.

^{45}P_{4}=\frac{45!}{(45-4)!}

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Hence, the number of ways are 3575880.

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Part (B) is an example of permutation where order matter.

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