It is 18°C at 8 am, and 14°C by noon. The change in temperature from 8 am to noon is
1 answer:
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<h3>I'm solving it using substitution method:-</h3><h3>7x+2y=3 {given}</h3><h3>=>7x=3-2y</h3><h3>=>x=(3-2y)/7-------(1)</h3><h3>x-3y=30 {given}</h3><h3>=>x=30+3y</h3><h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3><h3>=>3-2y=210+21y</h3><h3>=>3-210=21y+2y</h3><h3>=>-207=23y</h3><h3>=>y= -207/23= -9</h3><h3>putting the value of y on eqn(1):-</h3><h3>x=(3-2y)/7</h3><h3>x=>(3-2(-9))/7=(3+18)/7=21/7=3</h3><h2>Hence, x=3, y= -9</h2>✌️✌️❤️❤️
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Answer: sin = ±
Step-by-step explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A = & cos a=
,thus we get
sin =±
∴ sin =±
= ±
since ,360° < <450°
,180° < <225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!