A ternary digit is either 0, 1, or 2. How many sequences of 6 ternary digits containing a single 1 and a single 2 are there?
1 answer:
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<h2>The required poynomial equation is 
.</h2>
Step-by-step explanation:
Given,
The zeros of the polynomial are - 4, - 2, 1 and 4
To find, the polynomial equation = ?
We know that,
The polynomial equation = (x - A)(x - B)(x - C)(x - D)
= (x + 4)(x + 2)(x - 1)(x - 4)
= [(x + 4)(x - 4)] [(x + 2)(x - 1)]
= ()(
)
= ()(
)
=
=
Thus, the required poynomial equation is .