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natta225 [31]
3 years ago
6

How to find the surface area of it

Mathematics
1 answer:
larisa [96]3 years ago
3 0
6m times 8m=48m times 6m=288m times 10m equals 2,880
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Please help with my school
worty [1.4K]

Answer:

You didn't send the pool dimensions ill answer it when u do

Step-by-step explanation:

4 0
3 years ago
Aldo took a survey to show the number of people that liked different types of drinks.
Alecsey [184]
Umm I don’t really know if this is the answer but 26/the amount of the other flavors
8 0
3 years ago
Read 2 more answers
A line passes through the point (-4,-5) and had a slope of 5/2. Write an equation in slope-intercept form
daser333 [38]

Step-by-step explanation:

as we have a point and the slope, we can start with the point-slope form and then transform.

the point-slope form is

y - y1 = a(x - x1)

(x1, y1) being a point on the line, a being the slope.

the slope-interceot form is

y = ax + b

a being the slope again, b being the y-intercept (the y value for x = 0).

so, we have

y - -5 = 5/2 × (x - -4)

y + 5 = 5/2 × (x + 4) = 5x/2 + 5×4/2 = 5x/2 + 10

y = 5x/2 + 5

or

y = (5/2)x + 5

and this is already the slope-intercept form. all done.

4 0
1 year ago
You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
Write an expression with two terms. One term should have a coefficient with a variable and the other term should be a constant.
soldier1979 [14.2K]

Answer:

See Explanation

Step-by-step explanation:

Let us briefly explain the terms

  • Variable: This is the letter in the expression
  • Coefficient: This is the number beside the letter above
  • Constant: This is a number without any variable attached.

Let us take our expression with two terms to be: 3x+5

Coefficient =3

Variable =x

Constant =5

The word phrase of the expression is:

5 added to the product of 3 and a number.

3 0
3 years ago
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