Hope you can read this and hope it helps
Answer:
Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.
Given: △ABC, m∠B=90°
Find: AC and BK.
Short leg 90 degrees Long leg Hypotenuse
AB=12 90 BC=16 AC= ?
AK = ? 90 BK = ? AB=12
AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]
Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]
BK / 16 = AB / AC
BK / 16 = 12 / 20
BK = (3/5)16
BK = 48/5
another answer let see this
AB^2+BC^2=AC^2
12^2+16^2=AC^2
144+256=AC^2
400=AC^2
20=AC
# be careful#
I might be wrong.
I guess that in total all the angles equal to 180, that being said...
m∠BAC = 79
Try this option:
1. the sides of the biggest triangle are 16; x and √(16²-x²); the sides of the smallest triange are x;5 and y. The smallest triangle ~ the biggest triangle. Using the property of the similar triangles:

2. according to the Pyphagorean theorem (in the smallest triangle):

answer: y=√55.