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snow_tiger [21]
3 years ago
11

Can someone teach me how to do number 16???

Mathematics
2 answers:
kogti [31]3 years ago
7 0

Answer:

x=0

Step-by-step explanation:

it tells you that

∠LKJ=169

∠SKJ=x+95

∠LKS=74+2x

and by the figure we know that

∠LKJ=∠LKS+∠SKJ

so we have

169=x+95+74+2x\\\\169=3x+169\\\\169-169=3x\\\\0=3x\\\\x=0

solniwko [45]3 years ago
5 0

LKS + SKJ = LKJ

Substitute the numbers into the equation above.

74 + 2x + x + 95 = 169

Combine like terms

3x + 169 = 169

Subtract 169 from both sides

3x = 0

Divide both sides by 3

x = 0

SKJ = x + 95 = 0 + 95 = 95

LKS = 74 + 2x = 74 + 2(0) = 74 + 0 = 74

LKJ = 169

LKS + SKJ = LKJ

74 + 95 = 169. This proves that x = 0

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Answer:

(80.4942, 94.9052)

Step-by-step explanation:

The sample mean is x = 87.7.

The sample standard deviation is s = 11.26.

At 99% confidence and 19 degrees of freedom, the critical value is t = 2.861.

The confidence interval is:

x ± t (s/√n)

87.7 ± 2.861 (11.26 / √20)

87.7 ± 7.2053

(80.4947, 94.9053)

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bezimeni [28]
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write an equation for the translation of y= [x]. 16.5 units
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4 years ago
10 Points and brainlyest.<br><br> Thanks
fgiga [73]
I just checked and the right answer seems to be a) 5.5, I am truly sorry if it was incorrect but pls let me know if it was the right answer

7 0
4 years ago
Read 2 more answers
If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

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2 years ago
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Answer:

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