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3 years ago

Can someone teach me how to do number 16???

Mathematics

2 answers:

kogti [31]3 years ago

7 0

Answer:

x=0

Step-by-step explanation:

it tells you that

∠LKJ=169

∠SKJ=x+95

∠LKS=74+2x

and by the figure we know that

∠LKJ=∠LKS+∠SKJ

so we have

$169=x+95+74+2x\\\\169=3x+169\\\\169-169=3x\\\\0=3x\\\\x=0$

solniwko [45]3 years ago

5 0

LKS + SKJ = LKJ

Substitute the numbers into the equation above.

74 + 2x + x + 95 = 169

Combine like terms

3x + 169 = 169

Subtract 169 from both sides

3x = 0

Divide both sides by 3

x = 0

SKJ = x + 95 = 0 + 95 = 95

LKS = 74 + 2x = 74 + 2(0) = 74 + 0 = 74

LKJ = 169

LKS + SKJ = LKJ

74 + 95 = 169. This proves that x = 0

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Read 2 more answers

If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$